Modified: January 16, 2008

Forces: Maintaining Equilibrium or Changing Motion

Objectives:

  • Define force
  • Classify forces
  • Define friction force
  • Define normal force
  • Understand the difference between mass and weight
  • Determine the resultant of two or more forces using vector addition/composition
  • Resolve a force into component forces acting at right angles to each other using vector resolution
  • Determine whether an object is in static equilibrium, if the forces acting on the object are known
  • Detemine an unknown force acting on an object, if all the other forces acting on the object are known and the object is in static equilbrium

Introduction to Forces

A force is a push or a pull.
A force is something that has the ability to accelerate an object.

Forces are described in units of Newtons (N) or pounds (lb)

1 N will accelerate 1 kg at 1 m/s/s (F = m · a)

Also, 1N = 0.225lb and 1lb = 4.45N
 

How much do you weigh?

Classification of Forces

Internal forces: forces that act within the object or system whose motion is being investigated. Alone, these forces cannot change the motion of the body center of mass.

External forces: forces that act on an object as a result of its interaction with the environment surrounding it. These forces can change the motion of the body center of mass. Many sport biomechanists are only concerned with external forces.

Contact forces: forces that occur from contacting objects including solids and fluids. These forces are subdivided into two primary categories.

Friction
force: the component contact force that acts parallel to the surfaces in contact (due to the interactions of surface molecules). There is static and dynamic friction, and static friction > dynamic friction. The mathematical description of friction is: Friction Force = μ × Normal Force. Friction opposes motion, yet is also responsible for all horizontal motion. With the aforementioned equation in mind, how can you increase friction for any given circumstance?

 

An interesting discussion on race car tires...

 

Normal Contact Force: the component of a contact force that acts perpendicular to the surfaces in contact; both the normal and friction forces are essential to human movement.

Contact forces in running

Practice Problem: If the ground exerts a vertical force on a runner that has a magnitude of 2000 N and the coefficient of static friction between the shoe and the ground is 0.5, what is the maximum horizontal force he can generate under his shoe before slipping?

 

Non-contact forces: forces that do not require contact between two objects; the non-contact force of primary concern here is gravity, which causes an acceleration of -9.81 m/s/s, no matter how large or small the object is. With this in mind, how many N does one kg of mass weigh? (remember Newton's Second Law)

 

The Analysis of Multiple, Simultaneous Forces

Usually, such as in the aforementioned practice problem, there are more than one force involved in a physiological situation. A free body diagram is a tool for simultaneously analyzing multiple forces; it is a drawing of the analysis object with all external forces acting upon the object represented as arrows showing their points of application and directions.

Colinear forces: two or more forces that have the same line of action, but not necessarily the same direction; when adding these types of forces, one can use simple algebra.

Colinear Forces Practice Problem: A weight lifter (mass = 100 kg) lifts a weight (100 N). The vertical ground reaction force is 1000 N. What is the net force acting on the weight lifter? How will the center of mass be affected?

Non-colinear forces: if the forces are not colinear, you cannot algebraically sum each of the forces. You must use vector addition, or this if often called vector composition.

Vector addition, or composition: the addition of two or more non-colinear vectors, resulting in a resultant force.

Non-colinear Forces Practice Problem: The peak normal contact force for a runner is 1800 N and the simultaneous frictional contact force is 200 N. What does the resultant ground reaction force equal? Also, at what angle, in relation to the horizontal axis, is this resultant ground reaction force applied?

Vector resolution allows you to resolve one resultant force into perpendicular components; this might be thought of as the opposite of vector composition.

Another practice problem.



Static Equilibrium (ΣF = 0)

When an object is at rest and the forces acting on the object are in equilibrium, they result in a net force of zero.

Weightlifter example: The acceleration of this weightlifter is zero. If this person's mass = 80kg, and the mass of the barbell = 70kg, what must the ground reaction force equal?

Fgrf + Fbw + Fbb = 0

What would occur if the ground reaction force applied to the weightlifter = 2000 N?

How might this occur?


 

Additional Practice Problems:

  1. Using vector addition, calculate the resultant force acting on this gymnast
  2. Calculate the reaction forces applied to the child on a swing, assuming that the child is in static equilibrium (ΣF = 0). Calculate the resultant reaction force (FR), the two separate components of the resultant reaction force (FRX & FRY), and the orientation of the reaction force in relation to the horizontal (θ).
  3. The quadriceps pulls on the patella with a force of 1000 N. The patellar tendon also pulls on the patella with a force of 1000 N. A force from the femoral condyles is the only other significant force acting on the patella. If the patella is in static equilibrium and the knee is flexed to 120 degrees, what must the magnitude of the force that is applied to the patella by the femur be?

Chapter One Summary

  1. Forces are pushes or pulls that can be represented by vector quantities.
  2. External forces can cause changes in the motion of the center of mass; the most common are gravity and contact forces.
  3. Friction and normal forces constitute contact forces.
  4. Vector composition and resolution are important tools in the analysis of forces.
  5. Static equilibrium indicates that the sum of all external forces equals zero (ΣFx = 0 and Fy = 0).